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-4y^2+14y-6=0
a = -4; b = 14; c = -6;
Δ = b2-4ac
Δ = 142-4·(-4)·(-6)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-10}{2*-4}=\frac{-24}{-8} =+3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+10}{2*-4}=\frac{-4}{-8} =1/2 $
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